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QuímicaQuímica304 views·Updated Jun 14, 2026·2 pages

Diferencias entre Molalidad y Molaridad: Explicación Básica

user profile picture
Aguss@agustinibaceta

La concentración de soluciones es un concepto fundamental en química...

1
of 2
--- OCR Start ---
Molalidad (m)
def.
Cant. cle mol de soluto por KG de solvente
Form
1--
m=
mol. SolutO
KG. Solvente
jenn (Primero identific

Molalidad (m)

La molalidad es la cantidad de moles de soluto por kilogramo de solvente. Su fórmula es sencilla: m = mol soluto / kg solvente. Esta unidad es muy útil cuando trabajamos con cambios de temperatura.

Veamos un ejemplo: tenemos 5g de glucosa (C₆H₁₂O₆) en 250g de agua. Para calcular la molalidad, primero necesitamos convertir los gramos de glucosa a moles. La masa molar de la glucosa es 180g/mol C=12×6,H=1×12,O=16×6C=12×6, H=1×12, O=16×6, por lo que 5g equivalen a 0,027 moles.

Luego convertimos los gramos de solvente a kilogramos: 250g = 0,250kg. Finalmente, aplicamos la fórmula de molalidad: m = 0,027 mol / 0,250 kg = 0,108 mol/kg.

💡 Consejo: No confundas molalidad (m) con molaridad (M). La molalidad usa kilogramos de solvente, mientras que la molaridad usa litros de solución. ¡Esta diferencia es crucial en tus evaluaciones!

2
of 2
--- OCR Start ---
Molalidad (m)
def.
Cant. cle mol de soluto por KG de solvente
Form
1--
m=
mol. SolutO
KG. Solvente
jenn (Primero identific

Molaridad (M)

La molaridad representa la cantidad de moles de soluto por litro de solución (¡no de solvente!). Se calcula con la fórmula: M = mol soluto / litros solución. Es la unidad de concentración más común en el laboratorio.

Analicemos un ejercicio: tenemos 10g de NaCl en 500ml de solución. Primero calculamos los moles de NaCl. Su masa molar es 58g/mol Na=23g/mol,Cl=35g/molNa=23g/mol, Cl=35g/mol, así que 10g equivalen a 0,17 moles.

Como la solución total es 500ml, debemos convertirla a litros: 500ml = 0,5L. Ahora aplicamos la fórmula: M = 0,17 mol / 0,5L = 0,34 mol/L.

⚠️ Atención: El error más común es confundir el volumen de la solución con el del solvente. En molaridad, siempre usamos el volumen total de la solución, mientras que en molalidad consideramos solo la masa del solvente.

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QuímicaQuímica304 views·Updated Jun 14, 2026·2 pages

Diferencias entre Molalidad y Molaridad: Explicación Básica

user profile picture
Aguss@agustinibaceta

La concentración de soluciones es un concepto fundamental en química que nos permite expresar cuánto soluto hay en una solución. Veremos dos formas importantes de expresar la concentración: la molalidad y la molaridad, que aunque suenan parecidas, son diferentes y...

1
of 2
--- OCR Start ---
Molalidad (m)
def.
Cant. cle mol de soluto por KG de solvente
Form
1--
m=
mol. SolutO
KG. Solvente
jenn (Primero identific

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Molalidad (m)

La molalidad es la cantidad de moles de soluto por kilogramo de solvente. Su fórmula es sencilla: m = mol soluto / kg solvente. Esta unidad es muy útil cuando trabajamos con cambios de temperatura.

Veamos un ejemplo: tenemos 5g de glucosa (C₆H₁₂O₆) en 250g de agua. Para calcular la molalidad, primero necesitamos convertir los gramos de glucosa a moles. La masa molar de la glucosa es 180g/mol C=12×6,H=1×12,O=16×6C=12×6, H=1×12, O=16×6, por lo que 5g equivalen a 0,027 moles.

Luego convertimos los gramos de solvente a kilogramos: 250g = 0,250kg. Finalmente, aplicamos la fórmula de molalidad: m = 0,027 mol / 0,250 kg = 0,108 mol/kg.

💡 Consejo: No confundas molalidad (m) con molaridad (M). La molalidad usa kilogramos de solvente, mientras que la molaridad usa litros de solución. ¡Esta diferencia es crucial en tus evaluaciones!

2
of 2
--- OCR Start ---
Molalidad (m)
def.
Cant. cle mol de soluto por KG de solvente
Form
1--
m=
mol. SolutO
KG. Solvente
jenn (Primero identific

Sign up to see the content. It's free!

  • Access to all documents
  • Improve your grades
  • Join milions of students

Molaridad (M)

La molaridad representa la cantidad de moles de soluto por litro de solución (¡no de solvente!). Se calcula con la fórmula: M = mol soluto / litros solución. Es la unidad de concentración más común en el laboratorio.

Analicemos un ejercicio: tenemos 10g de NaCl en 500ml de solución. Primero calculamos los moles de NaCl. Su masa molar es 58g/mol Na=23g/mol,Cl=35g/molNa=23g/mol, Cl=35g/mol, así que 10g equivalen a 0,17 moles.

Como la solución total es 500ml, debemos convertirla a litros: 500ml = 0,5L. Ahora aplicamos la fórmula: M = 0,17 mol / 0,5L = 0,34 mol/L.

⚠️ Atención: El error más común es confundir el volumen de la solución con el del solvente. En molaridad, siempre usamos el volumen total de la solución, mientras que en molalidad consideramos solo la masa del solvente.

We thought you’d never ask...

What is the Knowunity AI companion?

Our AI companion is specifically built for the needs of students. Based on the millions of content pieces we have on the platform we can provide truly meaningful and relevant answers to students. But its not only about answers, the companion is even more about guiding students through their daily learning challenges, with personalised study plans, quizzes or content pieces in the chat and 100% personalisation based on the students skills and developments.

Where can I download the Knowunity app?

You can download the app in the Google Play Store and in the Apple App Store.

Is Knowunity really free of charge?

That's right! Enjoy free access to study content, connect with fellow students, and get instant help – all at your fingertips.

Most popular content: Solutions

1

Most popular content in Química

9

Most popular content

9

Can't find what you're looking for? Explore other subjects.

Students love us — and so will you.

4.6/5App Store
4.7/5Google Play

The app is very easy to use and well designed. I have found everything I was looking for so far and have been able to learn a lot from the presentations! I will definitely use the app for a class assignment! And of course it also helps a lot as an inspiration.

Stefan SiOS user

This app is really great. There are so many study notes and help [...]. My problem subject is French, for example, and the app has so many options for help. Thanks to this app, I have improved my French. I would recommend it to anyone.

Samantha KlichAndroid user

Wow, I am really amazed. I just tried the app because I've seen it advertised many times and was absolutely stunned. This app is THE HELP you want for school and above all, it offers so many things, such as workouts and fact sheets, which have been VERY helpful to me personally.

AnnaiOS user