Pre-Calculus29 views·Updated Jun 16, 2026·4 pages

Derivative of Inverse Trigonometric Functions

Drizzle Hinata@drizzlehinata

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This is about getting the derivative of inverse trigonometric functions.

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$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

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Pre-Calculus29 views·Updated Jun 16, 2026·4 pages

Derivative of Inverse Trigonometric Functions

Drizzle Hinata@drizzlehinata

Add to Google sources

This is about getting the derivative of inverse trigonometric functions.

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$

of 4

$ENGGMA TH2 CALCULUS 1 DERIVATIVE OF INVERSE TRIGONOMETRIC FUNCTIONS $ \frac{d}{dx} \arcsin u = \frac{du}{dx} \frac{1}{\sqrt{1-u^2}} $ $ \fra$